Boyle's Law Applies (P1V1 = P2V2 at Constant T)

Steps:

• Apply Boyle's law: initial pressure P1 = 3.0 × 10^5 Pa, initial volume V1 = 0.60 cm³; final pressure P2 = 1.0 × 10^5 Pa.
• Rearrange for final volume: V2 = (P1 × V1) / P2.
• Substitute values: V2 = (3.0 × 10^5 × 0.60) / (1.0 × 10^5) = 1.8 × 10^5 / 10^5 = 1.8 cm³.

Why C is correct:

• 1.8 cm³ exactly matches the Boyle's law calculation for volume expansion due to pressure decrease.

Why the others are wrong:

• A: 0.20 cm³ assumes compression (reversed pressures), opposite of expansion.
• B: 0.60 cm³ ignores pressure change, assuming constant volume.
• D: 2.4 cm³ from incorrect ratio (e.g., 4:1 instead of 3:1).

Final answer: C