O Levels Physics (5054)•5054/12/O/N/19

Explanation
Parallel vs. Series Spring Configurations
Steps:
- In parallel, load L is shared, so each spring supports L/2 and extends x = (L/2)/k, giving k = L/(2x).
- In series, full load L acts on each spring, so each extends δ = L/k = L / (L/(2x)) = 2x.
- Total extension is sum of individual extensions: 2 × 2x = 4x.
- Effective spring constant in series is k/2, so total extension = L/(k/2) = 2L/k = 2 × (2x) = 4x.
Why D is correct:
- In series, springs add extensions under full load L, doubling the extension per spring compared to parallel (Hooke's law: F = kδ).
Why the others are wrong:
- A: ¼x confuses series with parallel stiffness (effective k doubles in parallel, not halves).
- B: x assumes same extension as parallel, ignoring increased force per spring in series.
- C: 2x assumes each spring still extends x, but full L doubles each extension to 2x.
Final answer: D
Topic: Elastic deformation
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