mMCQ.

Navigation Menu

Step into mMCQ.

Launch mMCQ. diagnostic

Explore mMCQ.

MDCAT prepFree DiagnosticPricing & SubscribeSign in

Resources

Terms & Conditions

mMCQ.

© 2021 - 2025 mMCQ.All rights reserved.

WhatsApp
O Levels Physics (5054)•5054/11/O/N/19
Question 35 from 5054/11/O/N/19

Explanation

Lowest equivalent resistance maximizes current

Steps:

  • Current through ammeter is I = V / R_total, where V is fixed; minimize R_total for max I.
  • Assume equal resistor values R; series adds resistances, parallel reciprocals sum.
  • Calculate R_total: series = 3R (highest); full parallel = R/3 (lowest); mixed = between R/3 and 3R.
  • Lowest R_total arrangement yields greatest I.

Why A is correct:

  • A (all parallel) gives R_total = R/3 per Ohm's law, minimizing resistance and maximizing I = V / (R/3) = 3V/R.

Why the others are wrong:

  • B (two parallel, one series): R_total = R + (R/2) = 1.5R > R/3, lower I.
  • C (all series): R_total = 3R > R/3, much lower I.
  • D (two series, one parallel): R_total = (2R || R) = (2R * R)/(3R) = (2/3)R > R/3, lower I.

Final answer: A

Topic: Series and parallel circuits

Practice more O Levels Physics (5054) questions on mMCQ.me