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O Levels Physics (5054)•5054/11/O/N/18
Question 33 from 5054/11/O/N/18

Explanation

Magnetic force on current-carrying wire

Steps:

  • Recall force formula: F = B I L sinθ, where B is magnetic field strength, I is current, L is wire length, θ is angle.
  • Evaluate A: Reversing current and poles changes force direction but keeps B and I magnitudes same, so F unchanged.
  • Evaluate B: Reversing current reverses force direction but keeps magnitude same.
  • Evaluate C: Stronger magnet increases B, directly increasing F.
  • Evaluate D: Thicker wire with same I keeps I and B same, so F unchanged.

Why C is correct:

  • Force F is directly proportional to B (from F = B I L sinθ); stronger magnet raises B, raising F.

Why the others are wrong:

  • A: Reversals preserve B and I magnitudes, so F magnitude stays the same.
  • B: Only reverses force direction, not its size.
  • D: Same current I means same force, regardless of wire thickness.

Final answer: C

Topic: Forces on a current-carrying conductor

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