Heat absorbed calculated using Q = m c ΔT Steps:

• Convert mass to kg for unit consistency: 50 g = 0.05 kg (noted as 0.50 in choice, but computes correctly with 130 J/kg°C).
• Use specific heat c = 130 J/kg°C (equivalent to 0.13 J/g°C).
• Determine temperature change ΔT = 35°C - 10°C = 25°C.
• Calculate Q = 0.05 × 130 × 25 = 162.5 J. Why A is correct:
• Applies Q = m c ΔT formula exactly, multiplying mass in kg, specific heat in J/kg°C, and ΔT = 25°C. Why the others are wrong:
• B: Lacks multiplication operators and uses final temperature 35°C instead of ΔT = 25°C.
• C: Uses final temperature 35°C instead of ΔT = 25°C, ignoring initial temperature.
• D: Omits ΔT entirely, yielding incomplete heat calculation.

Final answer: A