Energy dissipated as heat in a resistor

Steps:

• Calculate power dissipated: P = I²R = (1.5 A)² × 4 Ω = 2.25 × 4 = 9 W.
• Convert time to seconds: t = 1 min = 60 s.
• Calculate energy: E = P × t = 9 W × 60 s = 540 J.
• Verify units: Joules (W·s).

Why C is correct:

• C (540 J) matches E = I²Rt from Joule's law, where thermal energy equals electrical power times time.

Why the others are wrong:

• A: Ignores time, giving just P × 1 s or similar error.
• B: Likely uses P = VI without voltage, or miscalculates I²R as 6 W then ×60.
• D: Doubles time or uses minutes directly, yielding 9 W × 160 s erroneously.

Final answer: C