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O Levels Physics (5054)•5054/11/M/J/24
Question 21 from 5054/11/M/J/24

Explanation

Shiny surfaces reduce heat loss by radiation

Steps:

  • Heat from hot food can escape via conduction, convection, or radiation.
  • Conduction and convection are minimized by the container's structure, but radiation is key for hot surfaces.
  • Shiny metal foil reflects infrared radiation, preventing net heat loss.
  • Thus, the foil acts as a poor emitter, keeping food warmer.

Why D is correct:

  • According to Kirchhoff's law of thermal radiation, good absorbers are good emitters; shiny surfaces are poor absorbers and thus poor emitters of infrared, reducing heat loss.

Why the others are wrong:

  • A: The container doesn't primarily trap air; it's the foil's surface properties that matter most for radiation.
  • B: Shiny foil is actually a poor absorber of infrared, not good, so it reflects rather than absorbs heat.
  • C: Metal is a good conductor, but the foil's thinness and shininess focus on radiation control, not conduction.

Final answer: D

Topic: Radiation

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