O Levels Physics (5054)•5054/12/M/J/23

Explanation
Rutherford's Alpha-Particle Scattering Reveals Nuclear Structure
Steps:
- Recall the experiment: Alpha particles fired at thin gold foil, most pass through but some deflect sharply.
- Analyze results: Large-angle deflections indicate a tiny, dense, positively charged nucleus repelling alphas via Coulomb's law.
- Connect to choices: Deflections quantify nuclear radius (about 10^-15 m) from scattering angles and impact parameters.
- Eliminate others: No evidence for fusion, decay, or isotopes in scattering patterns.
Why D is correct:
- Scattering follows Rutherford's formula, σ(θ) ∝ (Z1 Z2 e² / (4πε₀ E))² cot²(θ/2), where close approaches reveal the nucleus's small size by allowing most particles to pass undeflected.
Why the others are wrong:
- A: No fusion observed; experiment probed existing atomic structure, not merging nuclei.
- B: No decay products detected; focused on elastic scattering, not spontaneous emission.
- C: Isotopes differ in neutron number, but experiment measured charge (Z), not mass variants.
Final answer: D
Topic: The nucleus
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