O Levels Physics (5054)•5054/12/M/J/23

Explanation
Hooke's Law Defines Proportional Limit and Spring Constant
Steps:
- Locate the straight-line portion of the load-extension graph, where extension is proportional to load (Hooke's law: F = kx).
- Identify point Q as the end of this straight line, marking the limit of proportionality where deviation begins.
- Calculate the spring constant k as the gradient (slope) of the straight-line segment.
- Confirm the proportional segment is PR, so k equals the gradient of PR.
Why A is correct:
- Q is the limit of proportionality (end of straight line per Hooke's law), and k equals the gradient of PR (the proportional region, F/x).
Why the others are wrong:
- B: Q is correct limit, but QR gradient is in non-proportional (curved) region, invalid for k.
- C: R is beyond proportionality (in curved region), and PQ gradient is only partial segment, not full proportional k.
- D: R is not the limit (past proportionality), and QR gradient is curved, not for k.
Final answer: A
Topic: Elastic deformation
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