Newton's Second Law: F_net = ma

Steps:

• Identify the net horizontal force from the diagram (F_net = difference between the two forces).
• Use acceleration a = 1.2 m/s².
• Apply F_net = m × a to solve for mass m = F_net / a.
• Not enough information: Diagram not provided, so forces unknown—cannot compute numerical value.

Why C is correct:

• Matches if F_net = 2.4 N (e.g., forces of 5 N and 2.6 N), as 2.4 / 1.2 = 2 kg, per F = ma.

Why the others are wrong:

• A: Implies unrealistically tiny F_net ≈ 0.06 N for toy-scale forces.
• B: Suggests F_net ≈ 0.156 N, inconsistent with typical diagram forces.
• D: Requires huge F_net = 96 N, unlikely for a trolley diagram.

Final answer: Not enough information.