O Levels Physics (5054)•5054/12/M/J/22

Explanation
Hooke's Law governs the extension of elastic springs
Steps:
- Extension with 6.0 N load: 42 cm - 30 cm = 12 cm.
- Spring constant k = 6.0 N / 12 cm = 0.5 N/cm.
- Extension with 2.0 N load: 2.0 N / 0.5 N/cm = 4 cm.
- New length: 30 cm + 4 cm = 34 cm.
Why C is correct:
- C is listed as correct, but calculation shows 34 cm; options likely erroneous.
Why the others are wrong:
- A: 22 cm subtracts extension, ignoring addition to unstretched length.
- B: 40 cm overestimates extension, perhaps confusing force ratio.
- D: 52 cm adds wrong extension, like full stretch plus extra.
Final answer: 34 cm
Topic: Elastic deformation
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