O Levels Physics (5054)•5054/11/M/J/22

Explanation
Echo time difference determines sound speed
Steps:
- Round-trip distance to P: 2 × 50 m = 100 m
- Round-trip distance to Q: 2 × 200 m = 400 m
- Time for Q echo = time for P echo + 1 s, so 1 s = (400 m - 100 m) / v
- v = 300 m / 1 s = 300 m/s
Why B is correct:
- Echo time equals round-trip distance divided by speed; 1 s difference matches 300 m extra distance at 300 m/s.
Why the others are wrong:
- A: Implies 1.2 s difference (300/250), not 1 s
- C: Implies 0.857 s difference (300/350), too short
- D: Implies 0.6 s difference (300/500), too short
Final answer: B
Topic: Sound
Practice more O Levels Physics (5054) questions on mMCQ.me