Virtual magnified image in converging lens Steps:

• Identify object position: inside focal point of converging lens for virtual image.
• Trace rays: one parallel to axis bends away from focus; another through center undeviated.
• Determine image location: rays diverge, appearing to come from same side as object.
• Compare: image upright and larger than object for viewer.

Why B is correct:

• For object within focal length, lens formula $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$ (with ) yields positive (virtual), magnification and upright.

Why the others are wrong:

• A: Inverted occurs for real images when object beyond focal point.
• C: Smaller applies to real images with object far beyond 2f.
• D: Upright but smaller not possible for converging lens; would require diverging lens.

Final answer: B