O Levels Physics (5054)•5054/11/M/J/21
Explanation
Solar panel power = efficiency × incident power
Steps:
- Calculate incident power density: 10 kJ received in 1 s per 1 m² = 10 kW/m².
- Total incident power for 1 m² area: 10 kW/m² × 1 m² = 10 kW.
- Apply efficiency: 10 kW × 16% = 1.6 kW output power.
Why A is correct:
- Matches the formula P_out = η × (energy/time) × area, where η = 0.16 converts incident solar power to electrical power.
Why the others are wrong:
- B. 2.2kW: Uses ~22% efficiency instead of 16%.
- C. 6.4kW: Applies 64% efficiency, misinterpreting the percentage.
- D. 16kW: Treats 16% as a multiplier of 16, ignoring decimal conversion.
Final answer: A
Topic: Power
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