Average Speed from Distance and Time Interval

Steps:

• Identify the known distance $d$ between the two cameras.
• Record the time $t_1$ when the vehicle passes the first camera and $t_2$ when it passes the second.
• Calculate the time interval $\Delta t = t_2 - t_1$.
• Compute average speed as $v_{avg} = \frac{d}{\Delta t}$.

Why B is correct:

• Average speed is defined as total distance divided by total time, directly obtained from the given distance and time difference.

Why the others are wrong:

• A: Acceleration requires velocity change over time, but only average speed is found, not velocity variation.
• C: Maximum acceleration needs detailed velocity profile or multiple points, unavailable here.
• D: Maximum speed requires instantaneous velocity data, not just the average over the interval.

Final answer: B