Resultant force magnitude ranges from 5 N to 7 N for angles 0° to 90° Steps: - Use the formula for resultant magnitude: $R = \sqrt{3^2 + 4^2 + 2 \cdot 3 \cdot 4 \cdot \cos \theta} = \sqrt{25 + 24 \cos \theta}$, where $\theta$ is the angle between forces. - At $\theta = 0^\circ$, $\cos 0^\circ = 1$, so $R = \sqrt{25 + 24} = \sqrt{49} = 7$ N (maximum). - At $\theta = 90^\circ$, $\cos 90^\circ = 0$, so $R = \sqrt{25} = 5$ N (minimum). - For $0^\circ < \theta < 90^\circ$, $R$ varies continuously between 5 N and 7 N. Why A is correct: - 4 N is less than the minimum possible resultant of 5 N, per the parallelogram law of vector addition. Why the others are wrong: - B: 5 N occurs exactly at $\theta = 90^\circ$. - C: 6 N is between 5 N and 7 N, achievable at an intermediate …